Two natural numbers differ by 4 and the sum of their squares is 58 find the numbers?

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(1) Answers

Senti352

The firs number: a
The second number: b
a-b=4
a²+b²=58
Lets write b+4 instead of a.
(b+4)² + b² = 58
b²+8b+16+b²=58
2b²+8b+16=58
2b²+8b-42=0
b²+4b-21=0
(b+7).(b-3)=0
b=-7 or b=3
But, b can't equal to -7 because these number are naturel numbers. It must be positive.
b=3
for b=3; a-3=4; a=7