Mathematics
northdakotachick
61

HOW DO I DO THIS (DO NOT SOLVE FOR X) 1.) -2(x + 5) - 7 = 3x + 2(x - 5) 2.) 3(4x + 2) - 6x = 5x - 5(2+ x) 3.) 5(6x - 1) - 10x + 5 = 4(x + 10) - 4x 4.) -6(4 - x) + 12 = 3x - (x - 4)

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(1) Answers
keithsian

First of all you have to distribute the coefficient that applies to the parentheses. For example -2(x + 5) -2 is the coefficient In order to distribute, take the coefficient and multiply it by all the terms inside the parentheses, so -2 * x and -2 * 5 to get the answer -2x - 10. Now replace -2(x + 5) with -2x - 10 and then combine like terms. In question one, we combine -7 with -10 to get -17, so so far we got -2x - 17 on the left side. On the right side we get 3x + 2(x - 5). Now just follow the distribution steps. Take 2 and multiply it by all the terms inside of the parentheses. That gives us 2 * x and 2 * -5. So we get 2x - 10. Now replace 2(x - 5) with 2x - 10 and combine like terms. In order to combine like terms for a variable, we add the coefficients of the same variable together (ex. 1x + 6x = 7x). So in this equation, we take 3x and combine it with 2x to get 5x. The final part of the right side is 5x - 10. So question 1. is -2x - 17 = 5x - 10. For the other questions, follow the same process. Distribute and combine like terms.

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