Help Solve this Simultaneous Equation! Step by step please
1: 2x+y=3 5x-2y=12 2: Multiply the first equation by 2 (2) (2x+y=3) => 4x+2y=6 3: Add 4x+2y=6 + 5x-2y=12 ______________ 9x=18 The y's cancel out 9x/9=18/9 The 9's cancel out x=2 4: Plug (x=2) back into either equation but, I'm going to do the first one. It's easier. 2(2)+y=3 4+y=3 4-4+y=3-4 The 4's cancel out y=-1 Answer: (12,-1) If you plug (x) and (y) back in it will equal 3 for the first and 12 for the second.