Mathematics
JoelleBerey442
28

Find the slope of a line containing points (-2,8) and (5,3).

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(2) Answers
Puppies05

(-2,8)(5,3) slope = (y2 - y1) / (x2 - x1) slope = (3 - 8) / (5 - (-2) = - 5/7 <==

mia34

slope of a line that passes through [latex](x_1,y_1)[/latex] and [latex](x_2,y_2)[/latex] is [latex]\frac{y_1-y_2}{x_1-x_2}[/latex] given the points (-2,8) and (5,2) the slope between them is [latex]\frac{8-3}{-2-5}=\frac{5}{-7}=\frac{-5}{7}[/latex] the slope is [latex]\frac{-5}{7}[/latex]

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