Find the equation of the line that passes through the point (3,14) and is parallel to y=2/3x -6

y=mx+b m=slope paralell ines have same slope y=2/3x-6 slope is 2/3 the equation of aline that passes through (x1,y1) and has a slope of m is y-y1=m(x-x1) given (3,14) and slope is 2/3 y-14=2/3(x-3) y-14=2/3x-2 y=2/3x+12

you use the point slope formula  y-y1=m(x-x1) y-14=2/3(x-3) y-14=2/3x-2 +14      +14 y=2/3x+12