danyrompe7
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# Find the equation of the line that is perpendicular to y=3x+4 and that passes through the point (6,7)

The slope of the line perpendicular to y=3x+4 is -1/3 (negative reciprocal of 3). so point (6,7) is on the line y=(-1/3)x + b plug in x and y: 7=(-1/3)*6 +b 7= -2+b b=9 $y=-\frac{1}{3}x+9$