Mathematics
ReannaAduddell
16

Find the equation of a line in slope-intercept form that passes through the points (-2, 20) and (3, -10).

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(1) Answers
latinaberryhill

(-2,20)(3,-10) slope = (-10 - 20) / (3 - (-2) = -30/5 = - 6 y = mx + b slope(m) = -6 use either of ur points...(-2,20)..x = -2 and y = 20 sub and find b, the y int 20 = -6(-2) + b 20 = 12 + b 20 - 12 = b 8 = b so ur equation is : y = -6x + 8

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