(2) Answers
The distance between the two points is 3 sqrt(5)
distance along the x is 4 - 1 = 3 distance along the y is 8 - 2 = 6 using Pythagoras: 3^2 + 6^2 = 27 square root of 27 = 5.196 = 5.2 to nearest tenth
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The distance between the two points is 3 sqrt(5)
distance along the x is 4 - 1 = 3 distance along the y is 8 - 2 = 6 using Pythagoras: 3^2 + 6^2 = 27 square root of 27 = 5.196 = 5.2 to nearest tenth