Find the 39th term of the arithmetic sequence that starts with 4 and has a common difference of 6.
A. 232
B. 226
C. 238
D. None of these

+1

(1) Answers

ButterKing

Any arithmetic sequence can be expressed as:
a(n)=a+d(n-1), a=initial term, d=common difference, n=term number.
We are told that a=4 and d=6 so we have:
a(n)=4+6(n-1), so the 39th term is:
a(39)=4+6(38)
a(39)=4+228
a(39)=232