Mathematics
lesheac1266
10

Find the 39th term of the arithmetic sequence that starts with 4 and has a common difference of 6. A. 232 B. 226 C. 238 D. None of these

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ButterKing

Any arithmetic sequence can be expressed as: a(n)=a+d(n-1), a=initial term, d=common difference, n=term number. We are told that a=4 and d=6 so we have: a(n)=4+6(n-1), so the 39th term is: a(39)=4+6(38) a(39)=4+228 a(39)=232

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