Mathematics
BabyGirl0419
33

Find the 19th term of the arithmetic sequence whose common difference is =d5 and whose first term is =a12.

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(1) Answers
Genna57

an=a1+d(n-1) a1=first term d=common difference n=which term common difference is 5 first term is 2 an=5+2(n-1) 19th term is n=19 a19=5+2(19-1) a19=5+2(18) a19=5+36 a19=41 19th term is 41

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