Brian111
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# Evaluate fourth root of 9 multiplied by square root of 9 over the fourth root of 9 to the power of 5.

remember $\sqrt[n]{x^m} =x^ \frac{m}{n}$ and $(x^m)(x^n)=x^{m+n}$ and $\frac{x^m}{x^n}=x^{m-n}$ and $(x^m)^n=x^{mn}$ so $( \sqrt[4]{9})( \frac{ \sqrt{9} }{\sqrt[4]{9^5}})$= $( \sqrt[4]{9})( \frac{ \sqrt{2}{3^2} }{9^\frac{5}{4}})$= $( \sqrt[4]{9})( 3^\frac{2}{2} }{9\sqrt[4]{9}})$= $\frac{3}{9}$= $\frac{1}{3}$