Mathematics
Taylorjanae12
16

Consider the line y=9x-5. Find the equation of the line that is parallel to this line and passes through the point (5, -4). Find the equation of the line that is perpendicular to this line and passes through the point (5, -4).

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(1) Answers
KatriceLaigo

y = 9x - 5...the slope here is 9...a parallel line will have the same slope. y = mx + b slope(m) = 9 (5,-4)...x = 5 and y = -4 now we sub and solve for b, the y int -4 = 9(5) + b -4 = 45 + b -4 - 45 = b -49 = b so ur parallel line is : y = 9x - 49 y = 9x - 5...slope is 9. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is -1/9. y = mx + b slope(m) = -1/9 (5,-4)...x = 5 and y = -4 now we sub and solve for b, the y int -4 = -1/9(5) + b -4 = -5/9 + b -4 + 5/9 = b -36/9 + 5/9 = b - 31/9 = b so ur perpendicular line is : y = -1/9x - 31/9

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