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4. Area of a disk of diameter D : [latex]A= \pi*(D/2)^2\approx3.14*(3.5)^2=38.465[/latex] Assuming that you use the usual convention of rouding 5 to the greater number : A=38.47 5. Diameter of a circle of radius r : [latex]A= \pi D=47[/latex] hence [latex]D\approx47/3.14\approx14.97[/latex]
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