Angle theta lies in the second quadrant, and sin theta = 3/5. What is cos theta and tan theta?

Hello, 1) sin x=3/5==>x=126.869897...° (since in quadrant II) 2)==>cos x<0 cos x=-√(1-sin ² x)=-√(1-9/25)=-4/5 tan x=(3/5)/(-4/5)=-3/4 cotg x=-4/3 =1/tan x sec x=1/cos x=-5/4 cosec x=1/sin x=5/3