Mathematics
islandedormeus
37

Admission to the zoo is $6 for children and $9 for adults. On a certain day, 1480 people go to the zoo and $10,500 is collected. How many children and adults went to the zoo?

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(1) Answers
baliharsimran

6x+9y = 10500 x+y = 1480   Using elimination I get: 6x + 9y = 10500 -6x-6y = -8880 Add the 2 equations and I get 3y = 1620 Divide both sides by 3 and I get y = 540  Substitute that back in to 6x+9y = 10500.  I get that 6x+9*540 = 10500 9 * 540 = 4860  Subtract 4860 from both sides and I get 6x = 5640  Divide both sides by 6 and I get x = 940  So there must have be 940 children and 540 adults

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