Physics
EmmittZeiler
38

A student pushes a 12.0 kg box with a horizontal force of 20 N. The friction force on the box is 9.0 N. Which of the following is the best approximation of the box’s acceleration?

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(1) Answers
Joshuavillaurena

Fnet=m*a a= Fnet/m a=(20N[E]+9.0N[E])/ 12.0kg a=2.4167m/s^2 a ≈ 2.4m/s^2

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