Mathematics
Wollie
22

A nut mixture of peanuts and pecans at a small fair is $1.00 per pound of peanuts and $2.85 per pound of pecans. Over the entire day, 97 pounds of the nut mixture were sold for $254.25. If p is the number peanuts and n is the number of pecans, then the system of equations that models this scenario is: p+n=97 p+2.85n=254.25 Determine the correct description and amount of pounds for peanuts and pecans that were sold. A (12.0, 85.0)There were 12.0 pounds of peanuts and 85.0 pounds of pecans sold at the fair. B (75.0, 22.0)There were 75.0 pounds of peanuts and 22.0 pounds of pecans sold at the fair. C (85.0, 12.0)There were 85.0 pounds of peanuts and 12.0 pounds of pecans sold at the fair. D (22.0, 75.0)There were 22.0 pounds of peanuts and 75.0 pounds of pecans sold at the fair. I NEED HELP ASAP

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(1) Answers
nina8

A - 12.0, 85.0 You can solve this system of equations by subtracting p+2.85n-p-n=254.25-97 and if you solve that, you get 1.85n=57.25 and that can be simplified to n=85

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