a missile is launched from the ground. its height, h(x), can be represented by a quadratic function in terms of time, x, in seconds. after 1 second, the missile is 103 feet in the air; after 2 seconds, it is 192 feet in the air. find the height, in feet, of the missile after 5 seconds in the air. help!
here are several information's already given in the question. Based on those given information's, the answer to the question can be easily deduced. Height of the missile at o seconds = 0 feet = (0,0) Height of the missile after 1 minute = 103 feet = (1,103) Height of the missile after 2 seconds = 192 feet = (2,192) Then the quadratic equation can be represented by h(x) = 110x - 7x^2 Mow, after 5 seconds, h(5) = (110 * 5) - 7 * (5)^2 = 550 - 175 = 375 feet I hope the procedure is clear enough for you to understand.