Mathematics
soniaezeh
37

A line passes through the point (–3, 4) and its y-intercept is (0, –2). What is the equation of the line that is parallel to the given line and passes through the point (–5, 2)?

+3
(2) Answers
YolandeSehl667

hello :  Hello : let  A(-3,4)    B(0,-2) the slope is :   (YB - YA)/(XB -XA) =(-2-4)/(0+3) =-6/3 = -2 the equation of the line that is parallel to the given line and passes through the point (–5, 2)is : y-2 = -2(x+5)....(same slope (AB) )

CassKnight

First find the slope of equation #1. y = mx + b 4 = m(-3) - 2 Add 2 to both sides 6 = -3 m Divide both sides by-3 -2 = m Since we want parallel lines we will Use the same slop and the new point for equation #2. This time we know the slope so we will have to find the b (y-intercept). y = mx + b 2 = -2(-5) + b 2 = 10 + b Subtract 10 from both sides -8 = b y = -2x -8 this is the answer

Add answer