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# A line has a slope of -2 and contains the points (3, 5) and (4, y). The value of y is

$\sf{Slope =\frac{y_2-y_1}{x_2-x_1}$ The slope is -2. We have two points. (3,5) and (4,y) Plug it in and solve for y. $-2 =\frac{y -5}{4-3} \\\\-2 =\frac{y-5}{1}\\\\-2 =y -5\\\\y -5 = -2\\\\y -5 + 5 = -2 + 5\\\\y = -2 + 5\\\\\boxed{\bf{y=3}}$ The value of y is 3.