A ball is thrown into the air with a upward velocity of 40ft/s. Its height h in feet after t seconds is given by the function h=-16t^2+40t+10. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball's maximum height?
After 1.25 seconds the ball reaches its maximum at 35 feet. You can do this using a graphing calculator by replacing t with x.