A 4kg book sits on a table and your pet hamster puts his front paws on the book and pushes down with a force of 3N. What is the normal force?

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There are three forces acting on the book.  1. Force due to gravity 2. Force exerted downward by the hamster 3. Normal Force in reaction to the downward forces Since the book is not moving, the net force is zero. The summation of all forces must be zero. Then we could find the normal force which is unknown (denoted as x). ∑F = -(4 kg)(9.81 m/s2) - 3 N + x =0 ∑F = -39.24 N - 3N + x =0 x = 42 N Therefore, the normal force is 42 N.

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