Mathematics
Gigi12
18

4^2+3^2(7-5^0)^2+3 times 4-(1+3^2)^0

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(1) Answers
AndriaHettinger146

(4^2+3^2(7-5^0)^2+3)(4-(1+3^2)^0) = 1,029 First off, anything to the power of 0 equals one so, (4^2+3^2(7-5^0)^2+3)(4-1) (4^2+3^2(7-5^0)^2+3)(3) (16+9(7-1)^2+3)(3) (16+9(36)+3)(3) 1,029

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